Kobe Bryant is one of the greatest NBA players of all time, and the recognition of basketball fans the star is being demonstrated this season his farewell.

In its 20th and final season of his career, Kobe is receiving the affection of the fans of the United States. Each presentation outside the home, is cheered by fans, who showed once again idolatry by the star to vote 719,235 times on it to compete in the All-Star Game, which will take place on February 14 in Toronto. To get an idea, veteran received more than 200,000 votes more than the MVP (most valuable player) of last season and highlight the NBA this year so far, Stephen Curry. The owner of the Golden State Warriors was the second most voted athlete for the festive game, 510 202 times. Proof that the fans really want to see Kobe in his last 18 and All-Star career game. If the voting ended today, Kobe would have the company in the Western Conference team Curry, scorer of the season with an average of 31, 2 points per game, the double of the Oklahoma City Thunder Kevin Durant (349,473 votes) and Russell Westbrook (267,699), and Blake Griffin (182,107), the Los Angeles Clippers. On the side of the East, as expected, the most voted LeBron James was the wing, but well behind Kobe Bryant and Stephen Curry. The player of the Cleveland Cavaliers received 357,937 votes and must participate in its 12th consecutive game of stars. So far, the East team would also have a LeBron-mate Cavaliers point guard Kyrie Irving, who received 138,191 votes despite having lost most of the season through injury, and a former colleague of the Miami Heat star, Dwyane Wade, with 300,595. The roster would be completed by the pivot Andre Drummond, the Detroit Pistons, with 148,278 votes, and the wing Paul George of the Indiana Pacers, with 283,785.


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